I 
aaayush submit that here now that we all must do…..
We must upload our project but in a systematic way….
All the names have been submitted HERE
Members are therefore requested to upload their projects under their names only…. its for their benefit only or you will simply loose marks….
1 more thing…..
You must upload your project before 4th of march……
Regards
aaayush
ya its a great idea
hi we cn discuss ans solve out our matter here…..
Here is the photograph of this numerical
hey ankur…..
you can add new websites that you find in the snowkids website page. okay ???
Hi……
I have done various things for this site.
you can see recent changes
I want this site to be never ending…..
numericals about the second law are also important they will definetly come in SA i exam
Derivation
F is proportional to p2 - p1 / t
F is proportional to mv - mu / t
F is proportional to m [v - u / t]
F is proportional to m * a
F = k * ma (as k = 1)
F = Mass * acceleration
= kg m/s2
= N (newton)
where
F = Force
p2 = Final Momentum
p1 = Initial Momentum
m = Mass
u = Initial Velocity
v = Final Velocity
t = Time taken for u to become v
a = Acceleration
k = constant
can you do one thing??
jo rate ka option hai, woh site members ko nahi sikh raha
but agar dikhe toh woh cheating bhi kar sakate hain.
to klya tu rate option ka ek page bana sakata hai right panel mein???
hey ankur pay attention to what i hav said
Hey ankur..
If i m selected in the volvoadventure, then i might not be able to work for this site
So we want to finish this website as quick as possible.
ok. but i want you to concentrate on the themes and publishing of this site.
i will handle other work
here is it……
The second law of motion says
that is
F is proportional to p2 - p1 / t
F is proportional to mv - mu / t
F is proportional to m [v - u / t]
F is proportional to m * a
F = k * ma (as k = 1)
F = Mass * acceleration
= kg m/s2
= N (newton)
Hi… I want you to do the second law of motion and its derivation.
Now we will find the paper used in making of the airplane…..
Area of paper used = Area of region 1 + 2 + 3 + 4 + 5
= 2.49 + 6.5 + 4.5 + 4.5 + 1.3
Region 5
a trapezium can be divided into 1 triangle and 1 parallelogram.
Triangle
Area of equilateral triangle = root 3 / 4 * side * side
Area of equilateral triangle = root 3 / 4 * 1 * 1
Area of equilateral triangle = root 3 / 4
now
root 3 / 4 = 1/2 * b * h …(bcoz area of same triangle by any method will be same)
root 3 / 4 = 1/2 * 1 * h
root 3 / 4 * 2 = h
h = root 3 / 2
now we have got our altitude…. now we can find out the area of 5
Area of trapezium = 1/2 * sum of parallel sides * altitude
Area of trapezium = 1/2 * (2 + 1) * root 3 / 2
Area of trapezium = 1/2 * 3 * 1.73/2 (put 1.73 in place of root 3)
Area of trapezium = 1.3cm2 (after solving)
Region 3 n 3
Again easy…….
Area of right angled triangle = 1/2 * base * height
Area of right angled triangle = 1/2 * 6 * 1.5
Area of right angled triangle = 4.5cm2
that means, area of region 4 and 5 will be same. so Area of region 5 will also be 4.5cm2
Region 2.
Very simple…
Area of rectangle = Length * breadth
Area of rectangle = 6.5 * 1
Area of rectangle = 6.5cm2
Soln 1.
Region 1.
s = 5 + 5 + 1 / 2 (by herons formula)
s = 11/2
Area = under root of [11/2 * (11/2 - 5)(11/2 - 5)(11/2 - 1)]
Area = under root of [11/2 * 1/2 * 1/2 * 9/2]
Area = 3/4 * root of 11
Area = 2.49cm2
